Question

Can anyone simplify this for me

Answer 1

\[\frac{ 2^{n-1}+2n-1 }{ 26{n} }\]

Answer 2

its 2^n

Answer 3

\[\large \frac{ 2^{n-1}+2^n-1 }{ 26{n} }\]

like this ?

Answer 4

no its\[\frac{ 2^{n-1}+2n-1 }{ 2^n }\]

Answer 5

use the laws of exponents

Answer 6

\[\frac{ b^a }{ b^c }=b ^{a-c}\]

Answer 7

you have the same base for the first two

Answer 8

yes

Answer 9

ok tell me what you get and we can check it for you

Answer 10

the answer is 2^-n+n-1

Answer 11

is your middle term 2n or 2^n? on your original question

Answer 12

\[2^{n}+n-1\]

Answer 13

no I want to go back to your original posting first to make sure I am checking you correctly

Answer 14

\[\frac{ 2^{n-1} +2^n-1}{ 2^n}\]

Answer 15

is this the original question?

Answer 16

or is that middle term 2n

Answer 17

sorry

Answer 18

\[\frac{ 2^n+2n-1 }{ 2^n }\]

Answer 19

ok what happen to n-1 on the top one

Answer 20

i am sorry

Answer 21

no I just need to know the original problem do you want to type it again. I want to make sure you get the correct solution

Answer 22

take your time

Answer 23

now pls simplify

Answer 24

@ganeshie8

Answer 25

I can help you but I need to double check your original because you have given different versions. Please write your original for me.

Answer 26

yes i have checked

Answer 27

\[2^-n(2^n+2n-1)\]
\[2^n*2^-n=1\]
\[1/2^n*2n\] \[2n/2^n=2n^-2n\]
\[-1*1/2^n=-2^-n\]
1+2n^-2n-2^-n

Answer 28

Iam not sure if this is right or not

Answer 29

\[1+2n/2^n-1/2^n\]
\[2^n+2n/2^n-1/2^n\]