Question

what is the value of x2-x+3?

Answer 1

for which value of x?

Answer 2

yea? which value

Answer 3

hold on i typed the question wrong

Answer 4

\[\frac{ 2x-3 }{ x }=x+1\Rightarrow x^2+x=2x-3 \Rightarrow x^2-x+3=0\]
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Answer 5

so its 0

Answer 6

you tell me...

Answer 7

can u walk me through the steps

Answer 8

sure... first multiply both sides by x to get rid of the fraction\[\left( \frac{ 2x-3 }{ x } \right)\cdot x=\left( x+1 \right)\cdot x \Rightarrow 2x-3=x^2+x\]
then subtract (2x-3) from both sides.\[\begin{matrix}2x-3 =x^2+x\\ -2x+3 \,\,\,-2x+3 \\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0=x^2-x+3\end{matrix}\]
you end up with 0.

Answer 9

does that make sense?

Answer 10

yea
it5 makes perfect sense

Answer 11

thanks

Answer 12

one thing you should be aware of... x is originally in the denominator. we can't divide by 0 so we must insist that \(x\ne 0\). if at some point we solve for x and find that 0 is a solution to the analogous equation, we must exclude it from the solution set.

Answer 13

however, for this particular equation, x=0 is not a solution.

Answer 14

yea i know but thanks alot

Answer 15

you're welcome