I need help finishing a problem I am almost done with it but I got stuck!!! Here is the question. Using the Law of Cosine, in triangle RST, if r=14, s=9, t= 9 find the angle of S. I am down to -151/-168=cos S but when I divide that it doesn't work out!!!
@hartnn can you help me?
how did u get -151?
and 168 too :P which formula did you use? :O
This is what I did can you tell me if my answer is right?
ohhhhhh, your t= 6 ??? you put t=9 in your question
Ohhh opps sorry, I wasn't looking at the question when I typed it.
yes, your work is good angle S is indeed 26 degrees :)
Thank you. I have more so when I finish them can I post them to see if they are right?
sure :)
@hartnn Is this right?
that is also correct :) triangle sides are 15,28,17, right ? then yes, angle is 27 :)
Okay thank you, haha one more. :)
bring it on!
I need help on this one the question is Using the Law of Sine, in triangle ABC, if angle c= 135, angle b=10, side c= 45, what is the measure of a?
find measure of angle a, first! know how to ?
C=135, B=10, A= find out c= 45, a= required.
A+B+C= 180
dont you just add up the angles you know then subtract them from 180
a=25
i mean 35 sorry
yes, A =35 (sorry i lost my internet connection) now use the sine law ! \(\huge \dfrac{a}{\sin A }=\dfrac{c}{\sin C}\) only 'a' is unknown! :)
this is what i did
but you already know angle A .-. you need side =a so plug in A =35, C =135, c =45 in the sine law formula and find 'a' :)
I'm confused on how to do that
\(\huge \dfrac{a}{\sin 35}=\dfrac{45}{\sin 135}\)
multiply sin 35 on both sides
I'm a little confused
\(\huge \dfrac{a}{\sin 35}\times \sin 35=\dfrac{45}{\sin 135}\times \sin 35 \\ ~\\ \huge a=\dfrac{45}{\sin 135}\times \sin 35 =... \)
if you're still confused, use a calculator :)
I can't see all of the equation you posted
:O you can't ? ... ok, a/ sin 35 = 45 /sin 135 a = 45 sin 35 /sin 135 thats what i wrote!
ohh okay thank you
^_^
I got 34.2
my calculator gave me 36.5
i did it wrong the first time the second time i got 36.5
cool! :)
Thank you so much!!! :)
welcome ^_^
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