Question

A solution contains 72.0 g of HCl and 468 g of (C6H6). What is the mole fraction of benzene?

Answer 1

Molar Mass of HCL:(35.5+1)=36.5 grams
Molar Mass of C6H6:(12*6)+(1*6)=78 grams
Number of Moles:Mass(g)/Molar Mass(g/mol)
72/36.5=1.97260 moles of HCL 468/78=6moles of C6H6
Sum of Moles of Solution=6+1.97260
Moles of Solution=7.97260
Mole Fraction of benzene: Number of moles of Benzene/Number of Moles of Solution
6/7.97260