Question

Line AB contains points A (8, −4) and B (1, −5). The slope of line AB is...

−7

negative 1 over 7

1 over 7

7

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&({\color{red}{ 8}}\quad ,&{\color{blue}{ -4}})\quad B&({\color{red}{ 1}}\quad ,&{\color{blue}{ -5}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

Answer 2

all i have to do is the y2 -y1 thingy??? @jdoe0001

Answer 3

yes, to find the slope of a line from 2 points

Answer 4

is it b???@jdoe0001

Answer 5

well.. what did you get from \(\bf \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\quad ?\)

Answer 6

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&({\color{red}{ 8}}\quad ,&{\color{blue}{ -4}})\quad B&({\color{red}{ 1}}\quad ,&{\color{blue}{ -5}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -5}}-{\color{blue}{ (-4)}}}{{\color{red}{ 1}}-{\color{red}{ 8}}}\implies ?\)

Answer 7

i got b @jdoe0001

Answer 8

am i correct??@jdoe0001

Answer 9

hmm what did you get for the numerator?

Answer 10

numerator is top right?? @jdoe0001

Answer 11

yes

Answer 12

okay i got -1.. @jdoe0001

Answer 13

-1/7

Answer 14

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&({\color{red}{ 8}}\quad ,&{\color{blue}{ -4}})\quad B&({\color{red}{ 1}}\quad ,&{\color{blue}{ -5}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -5}}-{\color{blue}{ (-4)}}}{{\color{red}{ 1}}-{\color{red}{ 8}}}\implies \cfrac{-5+4}{-7}\implies \cfrac{-1}{-7}
\\ \quad \\
\implies \cfrac{1}{7}\)

Answer 15

ohhh okay yeahh i got it because a - and a - is a positive thanks!!! @jdoe0001

Answer 16

yeap

Answer 17

yw