Question

for f(x) = 4x+1 and g(x) = x^2 - 5

find [g/f](x)

Answer 1

super confused please help!

Answer 2

would it just be the two equations over each other?

Answer 3

pretty much, yes

Answer 4

\(\dfrac{g}{f}(x) = \dfrac{g(x)}{f(x)}\)

Answer 5

so it's x^2-5 / 4x+1

which is D?

Answer 6

Make sure the denominator does not get to zero by excluding the x value that would make it zero.

Answer 7

yeap

Answer 8

nope :(

Answer 9

look closely at A

Answer 10

yep it was A...

Answer 11

hmmm actaully listen to @aum above... you need to take into account the "constraints"

Answer 12

can x be -1/4? I mean this will get denominator to be 0

Answer 13

ahh ok so when doing the function problems the denominator can never be zero? Why is that?

Answer 14

well because say 25/0 =?

Answer 15

0/25 = 0 but 25/0 = ?

Answer 16

undefined. got it. makes sense now! thanks!

Answer 17

\(\bf \cfrac{0}{anything}=0\qquad \cfrac{anything}{0}=undefined\)

Answer 18

thank you!