How many grams of KOH can be formed when 58.00 grams of K2O react with 44.00 grams of H2O?
K2O + H2O yields KOH
Be sure to balance the equation.
17.30 grams
69.10 grams
137.8 grams
273.3 grams
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OpenStudy (superhelp101):
i am trying to solve this i got the balanced equation to be K2O+H2O yields 2KOH
OpenStudy (cwrw238):
K20 + H20 --> 2KOH
is correct
OpenStudy (superhelp101):
yep so what do I do then?
OpenStudy (cwrw238):
work out the molecular masses of each compound
from memory K = 39, O = 16 and H = 1
so 94 g of K2O react with 18 grams of water to give 112 g of KOH
OpenStudy (superhelp101):
sorry i am so confused is this right mol X g/mol= g
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OpenStudy (cwrw238):
you have excess of water
so 58 g of K2O will yield 58 * 112
------ grams of KOH
94
OpenStudy (cwrw238):
theres no need to work in moles - just use grams
OpenStudy (superhelp101):
oh okay. where did you get 112 and 94?
OpenStudy (cwrw238):
best to check on those figures i gave you - in case my memory is faulty