Question

(x/x^2−9)+(1/x+3)=(1)/(4x−12)

Answer 1

Can you factor any of those expressions?

Answer 2

hmm he hasn't said anything about factoring... he's just sharing the equation, just be happy is there =)

Answer 3

nice equation btw

Answer 4

I'll take his word that it's an equation then :p
I mean that IS an equals sign

Answer 5

I just have to solve for x. i think everything is already factored

Answer 6

hmm nothing is factored btw

Answer 7

i dont think you can factor anything? idk im really confused i just need to find the solution to the equation

Answer 8

hmmm well... you'd need to brush up on your factoring it seems

Answer 9

I'd say the same as ♂ , can you factor any of those? if not then you may want to brush it up some

Answer 10

i guess x^2-9 factors but what about the rest

Answer 11

hmmm how would you factor \(x^2-9\) anyway?

Answer 12

(x+3)(x-3)

Answer 13

hmm I see

Answer 14

\[\huge \frac{x}{(x+3)(x-3)}+ \frac{1}{x+3}= \frac{1}{4x−12}\]
this might help you visualize it

Answer 15

like cross multiply. (x)(x-3)+........then set it equal to 1/4x-12 which it already is. then solve

Answer 16

\(\bf \cfrac{x}{x^2-9}+\cfrac{1}{x+3}=\cfrac{1}{4x-12}\implies \cfrac{x}{(x-3)(x+3)}+\cfrac{1}{x+3}=\cfrac{1}{4x-12}
\\ \quad \\
\cfrac{x+(x-3)}{(x-3)(x+3)}=\cfrac{1}{4(x-3)}\implies \cfrac{2x-3}{(x-3)(x+3)}=\cfrac{1}{4(x-3)}
\\ \quad \\
4\cancel{ (x-3) }\cdot \cfrac{2x-3}{\cancel{ (x-3) }(x+3)}=1\implies \cfrac{8x-12}{x+3}=1
\\ \quad \\
8x-12=x+3\)

and surely you can get "x" from there

Answer 17

hint* fraction

Answer 18

that helped a lot, thank you so much!

Answer 19

yw

Answer 20

yw?

Answer 21

it means youre welcome

Answer 22

@ambiguousmathstudent are you being sarcastic? can't tell

Answer 23

yw == you're welcome

Answer 24

oh. embarrassing moment for me:(

Answer 25

haha dont worry bout it. thx guys