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Mathematics
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OpenStudy (anonymous):
Differentitate
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OpenStudy (anonymous):
The displacement of a body is given by
\[r=\sqrt{a ^{2}-b ^{2}} +tcos t ^{2}\]
OpenStudy (aravindg):
With respect to?
OpenStudy (anonymous):
where t is time and is constant ans a is constant. Its velocity is
OpenStudy (aravindg):
I hope you know velocity dr/dt
OpenStudy (anonymous):
yeahhh
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OpenStudy (cp9454):
should i tell u velocity
OpenStudy (aravindg):
Simply differentiate.
OpenStudy (anonymous):
lol wait
OpenStudy (ikram002p):
with respect to t right ?
OpenStudy (anonymous):
ofcourse
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OpenStudy (ikram002p):
^^
its easy then u can do it
OpenStudy (anonymous):
I got the part uhh after the + sign
but that (a^2-t^2)^1/2
OpenStudy (anonymous):
@AravindG
OpenStudy (aravindg):
t or b?
rvc (rvc):
\[\sqrt{a^2-b^2}=constant\]
\[\therefore its derivate =0\]
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rvc (rvc):
@No.name correct?
OpenStudy (anonymous):
|dw:1404880561829:dw|
Sorry it is ^
OpenStudy (aravindg):
Good. I thought so too.
Take a^2-t^2=u
Then do the normal differentiation with chain rule in the end.
rvc (rvc):
then
\[1/\sqrt{x}=-1/2\sqrt{x}\]
OpenStudy (anonymous):
I did that i am getting
\[\frac{ a-t }{ \sqrt{a ^{2}-t ^{2}} }\]
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rvc (rvc):
a is constant right?
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