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Mathematics 19 Online
OpenStudy (anonymous):

Differentitate

OpenStudy (anonymous):

The displacement of a body is given by \[r=\sqrt{a ^{2}-b ^{2}} +tcos t ^{2}\]

OpenStudy (aravindg):

With respect to?

OpenStudy (anonymous):

where t is time and is constant ans a is constant. Its velocity is

OpenStudy (aravindg):

I hope you know velocity dr/dt

OpenStudy (anonymous):

yeahhh

OpenStudy (cp9454):

should i tell u velocity

OpenStudy (aravindg):

Simply differentiate.

OpenStudy (anonymous):

lol wait

OpenStudy (ikram002p):

with respect to t right ?

OpenStudy (anonymous):

ofcourse

OpenStudy (ikram002p):

^^ its easy then u can do it

OpenStudy (anonymous):

I got the part uhh after the + sign but that (a^2-t^2)^1/2

OpenStudy (anonymous):

@AravindG

OpenStudy (aravindg):

t or b?

rvc (rvc):

\[\sqrt{a^2-b^2}=constant\] \[\therefore its derivate =0\]

rvc (rvc):

@No.name correct?

OpenStudy (anonymous):

|dw:1404880561829:dw| Sorry it is ^

OpenStudy (aravindg):

Good. I thought so too. Take a^2-t^2=u Then do the normal differentiation with chain rule in the end.

rvc (rvc):

then \[1/\sqrt{x}=-1/2\sqrt{x}\]

OpenStudy (anonymous):

I did that i am getting \[\frac{ a-t }{ \sqrt{a ^{2}-t ^{2}} }\]

rvc (rvc):

a is constant right?

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