Solve the system of equations.

y = x^2 - 4

y = 2x - 1

Select one:
a. (-2, 8) and (0, 4)
b. (-1, -3) and (-3, 5)
c. (-1, 3) and (3, -5)
d. (-1, 3) and (0, 2)

Question

Solve the system of equations.

y = x^2 - 4  

y = 2x - 1



Select one:
a. (-2, 8) and (0, 4)
b. (-1, -3) and (-3, 5)
c. (-1, 3) and (3, -5)
 d. (-1, 3) and (0, 2)

anonymous · Answer

y = x^2 - 4, y = 2x - 1 
So, you can write  x^2 - 4 = 2x - 1 
i.e x^2 -2x - 3 = 0 
Now  solve this quadratic equation.

anonymous · Answer

Can you solve it ?

anonymous · Answer

Factorization.

anonymous · Answer

What 2 numbers add up to -2 and multiply to -3?

anonymous · Answer

$$(X-? )(X+?) = 0$$

cp9454 · Answer

correct option is not given

zzr0ck3r · Answer

or just plug in the answers and see what works:)

anonymous · Answer

Trial and error

anonymous · Answer

It is given.

zzr0ck3r · Answer

o god dont medal me for that, his was much better,

cp9454 · Answer

then what is it @Johnbc

anonymous · Answer

Ha ha, it is great to know that you have a second method to solve this!

anonymous · Answer

@cp9454 Let the original poster learn to solve the problem.

anonymous · Answer

I'm sorry, but he's right.  Plugging in doesn't seem to yield a correct answer.

anonymous · Answer

(x,y) and (x,y)

anonymous · Answer

I know, and none of them work for both sets.

anonymous · Answer

the closest one is answer b and the (-3,5) doesn't work for the second equation

anonymous · Answer

Most likely error in choices provided if they do not.

anonymous · Answer

So we can agree that there is no correct answer amongst the ones we are provided with. Right?