Question

help with indefinite integral

Answer 1

Substitution problem?

Answer 2

yeah

Answer 3

yup do as earliear..

Answer 4

\[\int\limits_{}^{}\frac{ 6t^2-6 }{ 3t+13 } dt\]

Answer 5

this looks same as previous problem ? is there something specific you don't understand ?

Answer 6

or you can seperate the quotient and the remainder after dividing 6t^2-6 by 3t +13

Answer 7

i was never able to solve the problem with nimcompoop/ my helper before that.

Answer 8

\[6\int\limits_{}^{}\frac{ t^2-1 }{ 3t+13 } dt\]

Answer 9

long division... then on remainder.. ln something

Answer 10

Long division

Answer 11

lol

Answer 12

Do you know how to do long division?

Answer 13

ill give it a shot

Answer 14

better way here may be assuming 3u+13=t and du =3dt
and t = (13-u)/3 so t^2 = 1/9(169 -26u +1)

Answer 15

Take your time :)

Answer 16

Show your work using the drawing tool located under the text box using the button ""draw" if you can

Answer 17

That way we may help with any mistakes along the way.

Answer 18

ok