the town mayor plans to build a diagonal pathway for the rectangular town plaza whose length is 20 m longer than the width. if the pathway is 20 m shorter than twice the width, find the length of the pathway

Question

anonymous · Answer

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ikram002p · Answer

Hint :-
phytagorian thm ^

anonymous · Answer

how?

ikram002p · Answer

$\Huge\color{green}{c^2}=\color{blue}{a^2}+\color{gold }{b^2}$
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ikram002p · Answer

$\Huge (2x-20)^2 =x^2 +(x+20)^2$

ikram002p · Answer

$\large    4x^2-40x+400  =x^2 + x^2+20x+400 $

ikram002p · Answer

then you would have :-
$\large    2x^2-60x =0 $  

solve for x

ikram002p · Answer

$\large x(2x-60)=0$ 
so two cases 
x=0 (  ignore )

2x-60=0 $\rightarrow  x=30$

ikram002p · Answer

the length of the pathway =(2x-20) 
sub x= 30

length = 2 × 30 -20 =60 -20 =40 m