Question

a 10-ml pipette delivers 9.99, 10.01, 9.97, and 10.08 mL in an experiment. calculate the mean value and the average deviation from the mean

Answer 1

mean, is another word of average

\(\sf mean=\dfrac{9.99+10.01+9.97+ 10.08}{4}=10.0125=10.01~mL\)

I'm not entirely sure what they mean by average deviation, but i assume it's

\(\sf \Delta deviation=\dfrac{\sum|x_i-mean|}{N}\)

\(\sf =\dfrac{|9.99-10.01|+|10.01-10.01|+|9.97-10.01|+|10.08-10.01|}{4}=\dfrac{0.13}{4}\)

=0.0325=0.04

so the value is \(\sf10.01\pm0.04~mL\)