Carlisle conducted an experiment to determine if the there is a difference in mean body temperature for men and women. He found that the mean body temperature for men in the sample was 97.9 with a population standard deviation of 0.57 and the mean body temperature for women in the sample was 98.6 with a population standard deviation of 0.55.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 99% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

Question

Carlisle conducted an experiment to determine if the there is a difference in mean body temperature for men and women. He found that the mean body temperature for men in the sample was 97.9 with a population standard deviation of 0.57 and the mean body temperature for women in the sample was 98.6 with a population standard deviation of 0.55.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 99% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

anonymous · Answer

I posed one right now @ganeshie8

anonymous · Answer

I forgot how we did this problem @ganeshie8

ganeshie8 · Answer

start by finding the Margin of error for each

anonymous · Answer

how?

ganeshie8 · Answer

Men :
mean = 97.9
standard deviation = 0.57
margin of error for 99% confidence interval = ?

anonymous · Answer

by using the equation correct

anonymous · Answer

1.96*0.57/97.9