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Mathematics 16 Online
OpenStudy (anonymous):

Simplify and leave in radical form. https://media.glynlyon.com/g_alg02_ccss_2013/9/q13143.gif

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

might want to thing about getting like radicals?

OpenStudy (amistre64):

it might be easier to play with like this \[3^{1/2}~2^{1/3}\]

OpenStudy (anonymous):

I really need help on thisequation. Would it be square root 6?

OpenStudy (amistre64):

i got no idea what a simplified form means for this ... but one idea that comes to mind is, let: \[y=3^{1/2}~2^{1/3}\] \[log(y)=log(3^{1/2}~2^{1/3})\] \[log(y)=log(3^{1/2})+log(2^{1/3})\] \[log(y)=log(3)/2+log(2)/3\] \[6log(y)=3log(3)+2log(2)\] \[log(y^6)=log(3^3)+log(2^2)\] \[log(y^6)=log(3^3~2^2)\] \[y^6=3^3~2^2\] \[y=\sqrt[6]{3^3~2^2~}\] that might work out

OpenStudy (amistre64):

its not the sqrt(6) ....

OpenStudy (anonymous):

sqrt[6]{3^3~2^2~}\] is the answer??

OpenStudy (phi):

maybe the question is \[ \sqrt{3^3} \sqrt{2} \] ? otherwise it does not really simplify (though as amistre showed, you can write it in another form)

OpenStudy (amistre64):

im not sure what the answer is, but if i were to attempt it .. then i wrote out my attempt :) simplifying it from 2 factors into just a single term

OpenStudy (anonymous):

how would ou write it

OpenStudy (phi):

I'm suspicious it is 3 sqr(6)

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