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Find exact value of cos (-5pi/12)
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You could use the identity cos (A + B)
This would be cos(-45 + (-30)).
That expands to\[\cos(-45)\cos(-30)-\sin(-45)\sin(-30)\]
Each of those has values you can sub in.
\[\cos(-45)=\frac{ \sqrt{2} }{ 2 }\]\[\sin(-45)=-\frac{ \sqrt{2} }{ 2 }\]\[\cos(-30)=\frac{ \sqrt{3} }{ 2 }\]\[\sin(-30)=-\frac{ 1 }{ 2 }\]
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So fill in your values now:
\[(\frac{ \sqrt{2} }{ 2})(\frac{ \sqrt{3} }{ 2 })-(-\frac{ \sqrt{2} }{ 2 })(-\frac{ 1 }{ 2 })\]
Thank you so much. I got \[\frac{ \sqrt{6 - \sqrt{2}} }{ 4 }\]
That comes out to be\[\frac{ \sqrt{6}-\sqrt{2} }{ 4 }\]
Thank you :)
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You're welcome!
Crazy answer, but that is it!
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