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Mathematics 7 Online
OpenStudy (luigi0210):

Area in between curves:

OpenStudy (luigi0210):

I know the intercepts are 0, 3 and 4.. would I integrate from 0 to 4?

OpenStudy (kira_yamato):

I would say integrate from 0 to 3, do the same for 3 to 4. Then you can try doing the sum of the absolute values of the integrals (unless certain bounds have been set)

OpenStudy (luigi0210):

And it's always top curve minus bottom curve right?

OpenStudy (kira_yamato):

Yes

OpenStudy (luigi0210):

Alright, thank you ~

OpenStudy (phi):

Here is a plot notice that there is some ambiguity, unless they gave the x limits

OpenStudy (phi):

If you call the area from x=0 to 3 positive, the area from x=3 to 4 would (by convention) be negative.

OpenStudy (kira_yamato):

Btw intercepts are 0, 2, 4

OpenStudy (tkhunny):

Why do we care about intercepts? Don't we need intersections?

OpenStudy (luigi0210):

It never gave any restrictions so I just wanted to make sure where to go to and from where. And yea, sorry, I confuse interceptions and intersections alot..

OpenStudy (phi):

integrate from x=0 to 4 the top curve is the cubic, and the bottom curve is the quadratic

OpenStudy (phi):

the area is sum of rectangles of height h= top curve - bottom curve, and width dx

OpenStudy (tkhunny):

Thus, do [0,3] and [3,4] separately, since a different function is greater on these two sections. If you get 32/3, something has gone horrible wrong.

OpenStudy (phi):

after a quick google, you want the absolute value of each region (0 to 3) and 3 to 4 added together.

OpenStudy (luigi0210):

Alright, thanks you 3 :)

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