Area in between curves:
I know the intercepts are 0, 3 and 4.. would I integrate from 0 to 4?
I would say integrate from 0 to 3, do the same for 3 to 4. Then you can try doing the sum of the absolute values of the integrals (unless certain bounds have been set)
And it's always top curve minus bottom curve right?
Yes
Alright, thank you ~
Here is a plot notice that there is some ambiguity, unless they gave the x limits
If you call the area from x=0 to 3 positive, the area from x=3 to 4 would (by convention) be negative.
Btw intercepts are 0, 2, 4
Why do we care about intercepts? Don't we need intersections?
It never gave any restrictions so I just wanted to make sure where to go to and from where. And yea, sorry, I confuse interceptions and intersections alot..
integrate from x=0 to 4 the top curve is the cubic, and the bottom curve is the quadratic
the area is sum of rectangles of height h= top curve - bottom curve, and width dx
Thus, do [0,3] and [3,4] separately, since a different function is greater on these two sections. If you get 32/3, something has gone horrible wrong.
after a quick google, you want the absolute value of each region (0 to 3) and 3 to 4 added together.
Alright, thanks you 3 :)
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