The population of a local species of beetle can be found using an infinite geometric series where a1 = 960 and the common ratio is one forth. Write the sum in sigma notation, and calculate the sum (if possible) that will be the upper limit of this population. the summation of 960 times one fourth to the i minus 1 power, from i equals 1 to infinity. ; the sum is 1,280 the summation of 960 times one fourth to the i minus 1 power, from i equals 1 to infinity. ; the sum is divergent the summation of 960 times one fourth to the i power, from i equals 1 to infinity. ; the sum is 1,280
the summation of 960 times one fourth to the i power, from i equals 1 to infinity. ; the series is divergent
@ganeshie8
I need help on this @ganeshie8
Please @ganeshie8
At least can I tell what I would respond @ganeshie8
\[\large \sum \limits_{i=1}^{\infty} 960 \left(\frac{1}{4}\right)^{i-1}\]
familiar with infinite geometric series formula ?
Yes @ganeshie8
use it and find the infinite sum
\[\large S_{\infty} = \dfrac{a_1}{1-r}\]
\(a_1\) = 960 \(r\) = 1/4 plugin and simplify
1280
yes!
Ok so the answer would be A or C
A
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