If a copper wire has a resistance of 19.2 Ω at a temperature of 22.0 oC, what resistance does it have at 79.7 oC? (Neglect any change in length or cross-sectional area resulting from the change in temperature.)
ΔR=αR0ΔT. the law is for resistivity, but because length and area will be the same then you can convert resistivity to resistance. alpha is a constant
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/restmp.html if you used the constant in the above link \[r-19.2 = \alpha \times 19.2 \times ( 57.7)\] the alpha should be given
I guess I am still confused, I don't think alpha is given
http://www.cirris.com/learning-center/testing-guidelines/special-topics/177-temperature-coefficient-of-copper The information here gives you the temperature coefficient of resistance for copper, and gives examples of calculations that show you how to solve your question.
Any way alpha should mention in previous problem or in a table in your book.
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