Question

how do you write y+3=4(x-1) in standard form

Answer 1

Let's start by simplifying this equation as much as possible.

Answer 2

Let's first distribute on the right side the
4(x-1) to be 4x-4

Answer 3

Now we have,
y + 3 = 4x + 4

Let's now combine the constant terms by either subtracting 4 on both sides, or subtracting 3 on both sides.

Let's subtract 3 from both sides so we don't deal with negatives, which for making mistakes, we should avoid as much as possible.

y + 3 - 3= 4x + 4 - 3 -> y = 4x + 1

Answer 4

Now that we have y = 4x + 1, let's see what Standard Form looks like and what we need to do to rearrange this right.

Standard Form is Ax + By + C = 0

Ok so let's set it like this:
4x + 1 = y
then subtract y from both sides
4x + 1 - y = 0
switch the -y and 1 around
4x - y + 1 = 0

Ok there we go!!

Now we know...
A = 4
B = -1
C = 1


Our answer is 4x - y + 1 = 0

Answer 5

thank you!