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The difference quotient of the function y= f(x) is defined as (f(x+h)-f(x))/h for h does not equal 0. Compute the difference quotient for f(x)= 3x -2. Please show the steps and substitution for your solution.
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\[(f(x+h)-f(x))\div h\]
Take f(x+h) and plug the (x+h) into your equation 3x-2 what do you get?
I just tried to get the answer. Is it f(x)= -2x+2?
No
Okay, I'll need your help then.
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So I have 3(x+h) - 2(x+h) - (3x-2)/h
\[\frac{ 3(x+h)-2-[3x-2] }{ h }\]
Okay, so then you'd have 3x + 3h - 2 - 3x-2/h
You wouldn't do 2(x+h) because there is no variable attached to 2.
Is h=3?
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Yep
Yep
Awesome, thanks!
Anytime
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