sin^2x + sinx + cos^2x - 1

Question

imstuck · Answer

What, exactly, are you doing with this?

anonymous · Answer

I have to simplify but I don't know how

mathmale · Answer

Please post the instructions for this problem.  Note that (sin x)^2 is a better way to express "the square of the sine function" than is sin^2x.

Rewrite this problem using (sin x)^2 and (cos x)^2, please.

imstuck · Answer

As far as I can tell,  sin^2 x + cos^2 x = 1, so when you combine those into "1", you end up with 1 + 1 + sin(x) which is 2 + sin(x).  That's what I can see as far as simplifying goes.

mathmale · Answer

I agree with that.  The best way to approach the simplification of the given expression is to re-arrange the terms, so that you have (sin x)^2 + (cos x)^2 written in that manner (adjacent to each other), and can apply the identity presented by IMStuck.

mathmale · Answer

Mind writing the whole thing out, then rearranging the terms as indicated above, and then doing the final simplification?

anonymous · Answer

I think it should be 1-1+sin(x)= sin(x)

anonymous · Answer

oh I see!! so you have to cancel everything in parenthesis first and then finish

imstuck · Answer

nelsonjedi, I think you're right!  I DO think it should it should be 1 - 1 + sin(x) = sin(x).  You're right; I missed the -1 and had it as a +1.

anonymous · Answer

Been there done that

anonymous · Answer

i have couple more problems! can you help?

mathmale · Answer

Sure, so long as you'd please post them separately from this one.