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Mathematics 18 Online
OpenStudy (anonymous):

Factor. (How to solve?) 12x^3-23x^2+5x

OpenStudy (anonymous):

Well what is common to all three variables?

OpenStudy (anonymous):

x?

OpenStudy (anonymous):

So first factor out the x and what do you have?

OpenStudy (anonymous):

x(12x^2-23x+5)

OpenStudy (anonymous):

Great now we can still factor (12x^2-23x+5) by using the quadratic formula..

OpenStudy (anonymous):

I'm not sure where to go from here.

OpenStudy (anonymous):

Do you know the quadratic formula?

OpenStudy (anonymous):

No, we have not used it to solve these factoring problems.

OpenStudy (anonymous):

Sorry, we have. Is it ax^2+bx+c?

OpenStudy (anonymous):

Checking

OpenStudy (anonymous):

Right. But then I am not sure what exactly I have to do.

OpenStudy (anonymous):

No we need to factor 12x^2-23x+5..are you familiar with FOIL?

OpenStudy (anonymous):

Somewhat. From what I know I have to find "ac" which would be 12x5, right?

OpenStudy (anonymous):

So what are the factors of 12? And what are the factors of 5?

OpenStudy (anonymous):

1,2,3,4,6,12 and 1,5

OpenStudy (anonymous):

Correct now we have to figure out what values to use. Since 5 has only 1 factor we can solve half our problem (ax-1)(bx-5). Do you see this? Do you understand why it is minus for both equations?

OpenStudy (anonymous):

Because both negatives equal positive?

OpenStudy (anonymous):

Correct and also because in the equation ax^2+bx+c C is positive but bx is negative. Now the fun part. WE need to get (ax-1)(bx-5) to equal 12x^2-23x+5, we do this through trial and error of plugging in our factors for 12 for the values of a and b. Do you understand?

OpenStudy (anonymous):

I don't really understand :(

OpenStudy (anonymous):

Ok look at the factors for 12..Let's take 2 and 6 and plug them into our factor we get (2x-1)(6x-5) now does that equal 12^2-23x+5?

OpenStudy (anonymous):

No, it equals 12x^2-26x+5.. Or is that not correct?

OpenStudy (anonymous):

Good..now try another factor say.3 and 4. Solve and see if it equals 12^2-23x+5?

OpenStudy (anonymous):

12x^2-20x+5?

OpenStudy (anonymous):

Might want to check that one

OpenStudy (anonymous):

(3x-1)(4x-5), right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Check the 20x

OpenStudy (anonymous):

19x instead?

OpenStudy (anonymous):

Now flip the 3 and the 4 around and solve,

OpenStudy (anonymous):

(4x-1)(3x-5)

OpenStudy (anonymous):

12x^2-23x+5?

OpenStudy (anonymous):

So that is our other factors. So what is the answer?

OpenStudy (anonymous):

x(4x-1)(3x-5)?

OpenStudy (anonymous):

Great job...trust me this gets easier the more you practice...

OpenStudy (anonymous):

Oh my gosh, it is right. I submitted it and got the correct answer... you made it so much more easier to understand than the textbook and online instruction. Thank you so much, I spent hours on this problem.

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