Factor. (How to solve?) 12x^3-23x^2+5x
Well what is common to all three variables?
x?
So first factor out the x and what do you have?
x(12x^2-23x+5)
Great now we can still factor (12x^2-23x+5) by using the quadratic formula..
I'm not sure where to go from here.
Do you know the quadratic formula?
No, we have not used it to solve these factoring problems.
Sorry, we have. Is it ax^2+bx+c?
Checking
Right. But then I am not sure what exactly I have to do.
No we need to factor 12x^2-23x+5..are you familiar with FOIL?
Somewhat. From what I know I have to find "ac" which would be 12x5, right?
http://ts1.mm.bing.net/th?&id=HN.608013394737893209&w=300&h=300&c=0&pid=1.9&rs=0&p=0
So what are the factors of 12? And what are the factors of 5?
1,2,3,4,6,12 and 1,5
Correct now we have to figure out what values to use. Since 5 has only 1 factor we can solve half our problem (ax-1)(bx-5). Do you see this? Do you understand why it is minus for both equations?
Because both negatives equal positive?
Correct and also because in the equation ax^2+bx+c C is positive but bx is negative. Now the fun part. WE need to get (ax-1)(bx-5) to equal 12x^2-23x+5, we do this through trial and error of plugging in our factors for 12 for the values of a and b. Do you understand?
I don't really understand :(
Ok look at the factors for 12..Let's take 2 and 6 and plug them into our factor we get (2x-1)(6x-5) now does that equal 12^2-23x+5?
No, it equals 12x^2-26x+5.. Or is that not correct?
Good..now try another factor say.3 and 4. Solve and see if it equals 12^2-23x+5?
12x^2-20x+5?
Might want to check that one
(3x-1)(4x-5), right?
Yes
Check the 20x
19x instead?
Now flip the 3 and the 4 around and solve,
(4x-1)(3x-5)
12x^2-23x+5?
So that is our other factors. So what is the answer?
x(4x-1)(3x-5)?
Great job...trust me this gets easier the more you practice...
Oh my gosh, it is right. I submitted it and got the correct answer... you made it so much more easier to understand than the textbook and online instruction. Thank you so much, I spent hours on this problem.
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