Question

A 500-g sample of aluminum sulfate is reacted with 450 g of calcium hydroxide. If 500 grams of calcium sulfate are produced, what is the percent yield of the reaction? Please show all work

Answer 1

Aluminium has a charge of +3 and So4-2 ion interchange the charge to form Al2(SO4)^3
Calcium +2 and OH- interchane Charges Ca(OH)2
Al2(SO4)3+Ca(OH)2-->CaSO4+Al(OH)3
Balance :Write down the number of atoms that you have on each side of the equation.
On the Reactant Side: Al:2 S:3 O:14 H:2
On the Product Side: Al:1 S:1 O:7 H:3
Add a coefficient of 2 Al(OH)3
Al2(SO4)3+Ca(OH)2-->CaSO4+2Al(OH)3
On the Reactant Side: Al:2 S:3 O:14 H:2
On the Product Side: Al:2 S:1 O:10 H:6
Add a Coefficient of 3 to CaSO4
Al2(SO4)3+Ca(OH)2-->3CaSO4+2Al(OH)3
On the Reactant Side: Al:2 S:3 O:14 H:2 Ca:1
On the Product Side: Al:2 S:3 O:18 H:6 Ca:3
Add a coeffcient of 3 to Ca(OH)2
Al2(SO4)3+3Ca(OH)2-->3CaSO4+2Al(OH)3
On the Reactant Side: Al:2 S:3 O:18 H:6 Ca:3
On the Product Side: Al:2 S:3 O:18 H:6 Ca:3
Write out each mass given
if 500 grams of CaSO4 are produced this is the actual yield
500*1mole of Al2(SO4)3/342.15 Al2(SO4)3=1.46 Moles*3 moles of CaSO4/1mole of Al2(SO4)3=4.38*136=595.68
if 450 *1 mole/74.=6.08 mole*3 moles of CaSO4/3 Moles of Ca(OH)2=6.08*136=827.02 grams
Choose the smaller Number
(Actual Yield/Theortical Yield)*100
(500/595.68)*100=84.93

Answer 2

wow, thank you!

Answer 3

your welcome :)