Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

Algebra 2 help plz

OpenStudy (anonymous):

Let f(x) = 9x - 2 and g(x) = -x + 3. Find f(g(x)). -9x - 2 -9x + 5 -9x + 25 -9x + 27

OpenStudy (anonymous):

Let f(x) = -4x + 7 and g(x) = 10x - 6. Find f(g(x)). -40x + 24 -40x + 31 -40x + 64 -40x + 70

OpenStudy (anonymous):

im not sure because i dont see the answer i got

OpenStudy (anonymous):

well because f(x) = g(x) so g(x) is x of f(x) so you put the eqaution of g(x) into the the equation of f(x)

OpenStudy (kagıtucak):

In both of them, you just need to put g(x) instead of x in f(x). For the first one: f(x)=9x-2 then f(g(x))=9(-x+3)-2 =-9x+27-2 =-9x+25 I leave the second one to you

OpenStudy (anonymous):

yeah what kagitucak said or wrote

OpenStudy (anonymous):

i did that but got -9x-1?? and -40x-1??

OpenStudy (anonymous):

and the second one is the same step

OpenStudy (anonymous):

what did i do wrong??

OpenStudy (anonymous):

yeah because you subtracted first instead of multiplying what was in the paranthesis

OpenStudy (anonymous):

so would it be -40x+33??

OpenStudy (anonymous):

31

OpenStudy (anonymous):

for the second one??

OpenStudy (anonymous):

i thought the first one was -9x+25

OpenStudy (anonymous):

yes you are correct

OpenStudy (anonymous):

ok and wb the second one??

OpenStudy (anonymous):

second one would be B

OpenStudy (anonymous):

are you fuys good with sqrt and extraneous and non extraneous??

OpenStudy (anonymous):

Square root of x plus 6 − 4 = x Square root of x plus 6 − 4 + 4 = x + 4 Square root of x plus 6 = x + 4 (Square root of x plus 6)2 = (x + 4)2 x + 6 = x2 + 8x + 16 x + 6 − 6 = x2 + 8x + 16 − 6 x = x2 + 8x + 10 x − x = x2 + 8x + 10 − x 0 = x2 + 7x + 10 0 = (x + 2)(x + 5) x + 2 = 0 x + 5 = 0 x + 2 − 2 = 0 − 2 x + 5 − 5 = 0 − 5 x = −2 x = −5 Solutions = −2, −5 What error did Israel make?

OpenStudy (anonymous):

He subtracted 6 before subtracting x. He added 4 before squaring both sides. He factored x2 + 7x + 10 incorrectly. He did not check for extraneous solutions.

OpenStudy (anonymous):

is it d??

OpenStudy (anonymous):

hmmm

OpenStudy (anonymous):

i think its d i dont see anything else worng

OpenStudy (anonymous):

well i think that it is D too but im not sure because i hate word problems

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

wb this one?? Violet was carrying around the steps to solve Square root of 3x plus 1 = 4. On her way through the Math Factory, Violet dropped them and they mixed with other steps. Put the correct steps in order to solve Square root of 3x plus 1 = 4. A. Subtract 1 from both sides B. Subtract 4 from both sides C. Square root both sides D. Square both sides E. Divide by 3 from both sides F. Divide by 4 from both sides First A, then E, then D First D, then B, then A First D, then A, then E First C, then E, then A

OpenStudy (anonymous):

so the equation is\[\sqrt{3x + 1}=4\]

OpenStudy (anonymous):

if so first is D

OpenStudy (anonymous):

then A

OpenStudy (anonymous):

then E

OpenStudy (anonymous):

sorry my comp spazed

OpenStudy (anonymous):

@ShailKumar

OpenStudy (anonymous):

i have a diff q those where answered

OpenStudy (anonymous):

Post it

OpenStudy (anonymous):

Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A. Launch Area: (1,2), Point A: (0, 3)

OpenStudy (anonymous):

i got x+y=2

OpenStudy (anonymous):

How did you get that ?

OpenStudy (anonymous):

i got -1/1 and plugged it in to y-2=-1(x-0)

OpenStudy (anonymous):

then cpmverted

OpenStudy (anonymous):

You have plugged in wrong point. You should plug in e.g (1,2) then you should get y-2 = -1(x-1)

OpenStudy (anonymous):

ohhhhhhhh

OpenStudy (anonymous):

so x+y=1

OpenStudy (anonymous):

??

OpenStudy (anonymous):

Yes. Now it's correct. :)

OpenStudy (anonymous):

Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A to Point B. Point A: (0,3), Point B: (-3, 0)

OpenStudy (anonymous):

Show me your work

OpenStudy (anonymous):

y-3=-3(x-0)

OpenStudy (anonymous):

@AnswerMyQuestions

OpenStudy (anonymous):

the eqaution is simple just plug in the points y - y2 = m(x-x2)

OpenStudy (anonymous):

Slope is 1

OpenStudy (anonymous):

oh yeah but wouldnt it be negative??

OpenStudy (anonymous):

No

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Determine the equation of the line, in slope-intercept form, that will get your spacecraft from Point B to Point C. Point B: (-3, 0), Point C: (-1, -4)

OpenStudy (anonymous):

its the same thing

OpenStudy (anonymous):

find the slope plug it in

OpenStudy (anonymous):

slope is y2-y1/x2-x1

OpenStudy (anonymous):

Slope intercept form is y = mx+c

OpenStudy (anonymous):

the slope is -2 right

OpenStudy (anonymous):

c is the intercept.

OpenStudy (anonymous):

^

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

so y=-2x+??

OpenStudy (anonymous):

y-0=-2(x+3)

OpenStudy (anonymous):

y=-2x=5??

OpenStudy (anonymous):

6

OpenStudy (anonymous):

-6

OpenStudy (anonymous):

y=-2x-6 lol

OpenStudy (anonymous):

that correct

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

yay lol

OpenStudy (anonymous):

5) Convert the equations you arrived at in question 2 into slope-intercept form. Make sure to include all of your work.

OpenStudy (anonymous):

x+y=1

OpenStudy (anonymous):

??

OpenStudy (anonymous):

i have to put x+y=1 in to slope intercept

OpenStudy (anonymous):

is it y=-x+1

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

last one lol

OpenStudy (anonymous):

Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences.

OpenStudy (anonymous):

wait first close this tab and create a new one please with all the scenarios together

OpenStudy (anonymous):

ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!