Question

ugh

Answer 1

@FriedRice @ShailKumar

Answer 2

:D

Answer 3

y=-x+1
y=-2x-6
y-3=1(x+0)
x+7=1

Answer 4

Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences.

Answer 5

what do you think

Answer 6

i know there is idk what they are though

Answer 7

What are the values of x can y = -x+1 take ?

Answer 8

idk??

Answer 9

make a "T" table it will let you know the domain and range

Answer 10

a t table of what

Answer 11

Think about y = 1/x, What if you put x= 0 ?

Answer 12

then itd be 0

Answer 13

What would be 0 ?

Answer 14

1/0

Answer 15

i know but what will that doz??

Answer 16

it will give you the domain and range

Answer 17

but how do i know how far to go??

Answer 18

That is undefined! That means y = 1/x is valid for any value of x except x = 0.

Answer 19

nvm just listen to shailkumar

Answer 20

so x cant = 0 is the retsriction for d

Answer 21

Similarly think about values of x for which y = -x + 1 is not defined.

Answer 22

1

Answer 23

for x = 1 you get y = 0. But that is defined. Actually, y = -x+1 is defined for all values of x and there is no restriction.

Answer 24

ok now im getting confused

Answer 25

i though the restriction was x≠0

Answer 26

??

Answer 27

can you just explain why there will be restrictions on the domain and range?? plz

Answer 28

1/0 is undefined and denoted by \(\infty \). So any thing like \(\frac{\infty}{\infty} \ or \ \infty \times \infty\) are called undefined.

Answer 29

ok can you explain why there is restrictions lol

Answer 30

in y = -x+1, there is no value of x for which y is in some form of \(\infty\). That's why there is no restriction.

Answer 31

can you explain why there is restrictions for x and y for all of them

Answer 32

like what causes there to be restrictions

Answer 33

@ShailKumar why is there restrictions

Answer 34

in all equations not just that 1

Answer 35

There is no restriction in any equation.

Answer 36

no like can you explain why restrictions exist

Answer 37

and what they do

Answer 38

Broadly there are two reasons if we have 1/0 or \(\sqrt{-1}\) in the equation.

Answer 39

So, tell me what is 5/1 = ?

Answer 40

5??

Answer 41

Right! Now 5/0= ??

Answer 42

0

Answer 43

4/2 = ?

Answer 44

2 what does this have to do with anything??

Answer 45

So 4/2 means that you have divided 4 in 2 parts each part measures 2.
5/0 means you have divided in 0 parts ! What does that mean ?

Answer 46

idk youre confusing mehhhhhhhhhhhhhh!!!

Answer 47

You cannot divide something in zero parts. 5/0 has no meaning i.e 5/0 is undefined.

Answer 48

The value of x for which y is not defined should not be considered!

Answer 49

ok but restrictions are because you want whatever youre doing in s certsin place

Answer 50

E.g in y = 5/x, you cannot take x = 0. Why ?

Answer 51

idk nevermind i give up

Answer 52

Because y = 5/0 is not defined! This is the restriction.

Answer 53

but thats not the restrictions im talking about

Answer 54

this is what my teacher told me

Answer 55

We are looking for you to explain using complete sentences what restrictions would apply in this scenario. Since your Spacecraft has a specific starting and ending points for each leg of the journey, we wouldn’t be able to have any values past those points and remain on each trajectory. Think about how that would affect your domain and range. Recall that the domain is the set of all x-values that satisfy the equation and the range is the set of all y-values that satisfy the equation

Answer 56

y = -x+1, what are the points spacecraft is commuting between ?

Answer 57

i already closed it but th though