Evaluate.

Question

Evaluate.

anonymous · Answer

$$\sqrt[3]{343}+\frac{ 3 }{ 4 }\sqrt[3]{-8}$$

dumbcow · Answer

$$\sqrt[3]{343} = 7$$
$$\sqrt[3]{-8}=-2$$

anonymous · Answer

what do i do with the $$\frac{ 3 }{ 4 }$$

anonymous · Answer

@dumbcow

mathmale · Answer

First, look at that 343.  Is this a perfect cube?  If so, of what number?
What are the cubes of 5, 6 and 8?

Next:  The square root of -1 is defined as the imaginary operator, i.

The 3/4 (better typed as (3/4) is a coefficient.  Find the cube root of -8 and then preface it with (3/4).

mathmale · Answer

Your posted problem consists of the sum of two terms, each of which has to be simplified before the addition takes place.$$\sqrt[3]{343}+\frac{ 3 }{ 4 }\sqrt[3]{-8}$$will look like$$(  ?  ) +(3i/4) (  ?  )   $$when done.

anonymous · Answer

the answer is $$5\frac{ 1 }{ 2 }$$

mathmale · Answer

Your "answer" must have a real part and an imaginary part.

The form of such an "answer" is a + ib, where i is the imaginary operator.

What is the cube root of 343?
What is the cube root of 8?
What is the cube root of -8?
What is the product of (3/4) and the cube root of -8?