Question

cube root of 7 multiplied by the square root of 7 over sixth root of 7 to the power of 5
Solve.. Please help!!!

Answer 1

\[^3\sqrt7\sqrt7/^6\sqrt7^5\]

Answer 2

lets first use this :
\(\huge \sqrt[n]x = x^{1/n}\)

so what about
\(\large \sqrt[3]7 = ... ?\)

Answer 3

would it be \[7^1/3\]

Answer 4

1/3 is supposed to be in exponent form

Answer 5

yes, i know :)

then you can also answer me
\(\sqrt[6]7^5 = ... \\ \sqrt 7 = ...\)

Answer 6

\[^6\sqrt7^5 = 7^5/6\] and
\[\sqrt7\] stays the same right?
I am sorry, but I am not really good at this....

Answer 7

you're good!
both of your answers are correct :)
and for
\(\sqrt 7\)
it becomes
\(\Large 7^{1/2}\)

Answer 8

oh ya....

Answer 9

now moving to next rule :
\(\huge x^m x^n = x^{m+n}\)

so