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OpenStudy (anonymous):
Hey i got it
OpenStudy (shubhamsrg):
I thought you got it ?
How did you get it ?
OpenStudy (anonymous):
want to share a nice problem with you , forget this problem
OpenStudy (anonymous):
I know you will know it but still
OpenStudy (anonymous):
It is not big don't worry
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OpenStudy (shubhamsrg):
:|
OpenStudy (shubhamsrg):
log will come to rescue in such cases.
OpenStudy (anonymous):
^ :) yess
OpenStudy (shubhamsrg):
Sure is interesting :)
OpenStudy (kainui):
I actually really am interested in this particular equation and have thought of it in depth.
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OpenStudy (anonymous):
I am actually interested in The subject
"CALCULUS"
OpenStudy (anonymous):
Newton and Leignbez were great
OpenStudy (kainui):
I had accidentally discovered an alternate route to taking the derivative of this function. If you think of how you might normally take the derivative of:
y=b^x
and x^n
You can then add these results to get the derivative, almost like a cheating method of using logarithm rules for the product rule.
\[\Large \frac{d}{dx}(x^x)=x*x^{x-1}+x^xlnx\]