What are the amplitude, period, phase shift, and midline of f(x) = 7 cos(2x + π) − 3?
Amplitude = −3; period: π; phase shift: x = negative pi over 2; midline: y = 3 Amplitude: 7; period: π; phase shift: x = negative pi over 2; midline: y = −3 Amplitude: 7; period: 2π; phase shift: x = pi over 2; midline: y = 3 Amplitude: −3; period: 2π; phase shift: x = pi over 2; midline: y = −3
If f(x) = Acos(Bx + C) + D, then: Amplitude = A Period = (2*pi) / B Phase shift = -C / B Midline is: y = D
Okay, so would I use that formula for all of them?
Yes. And the same formula applies if it is sine function instead of cosine.
okay I'll see what I get then let you know
Alright.
how do i find x?
Not sure what you mean? For this problem you don't have to solve for x.
But like in the formula thing there's x...
You probably think i'm really stupid ehhh sorry :(
You just compare the given function to the general function and identify the constants A, B, C and D and then plug it into the formula: f(x) = 7 cos(2x + π) − 3 Compare this to the general form, f(x) = Acos(Bx + C) + D A = 7 B = 2 C = π D = -3 Amplitude = A = 7 Period = 2π / B = 2π / 2 = π ....
OHHH okay thank you so muchhhh sorry for burdening you with all of my math problems I seriously do appreciate it :)
C is the correct answer right?
Hey, no problem at all. We are here to assist. Not C. C has a period of 2π. We calculated the period above to be π. Amplitude = A = 7 Period = 2π / B = 2π / 2 = π To finish the other two: Phase shift = -C / B = -π / 2 Midline is: y = D; y = -3
Okay. It's A?
?!
The answer we got above is: Amplitude: 7; period: π; phase shift: x = -π / 2; midline: y = −3
Choice B.
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