Question

Solve 2 log x = log 64.

x = 8

x = ±8

x = 32

x = 128

Answer 1

rewrite the equation using index laws

\[\log(x^2) = \log(64)\]

so now you have what appears to be the same base...

then you can say

\[x^2 = 64\]

solve for x

and alternative is

\[2\log(x) = \log(8^2)\]

and then using log laws

\[2\log(x) = 2 \log(8)\]

you need to think about the solution can you find the log of a negative

Answer 2

idk how to solve the problem

Answer 3

well look at

log(x) = log(8)

what do you think is the value of x....?

Answer 4

8?

Answer 5

yes... that's the answer

Answer 6

so simple. thank you