Question

Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20 cospi over 15 + 30, where H represents the height of the person above the ground in feet at t seconds.

Answer 1

Part 2: How long does the Ferris wheel take to make one complete revolution?
Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?

Answer 2

part 1 I believe is 28

Answer 3

Given equation follows the form: y=Acos(Bx-C)+D, A=amplitude, period=2π/B, C/B=phase shift, D=vertical shift

Answer 4

thanks :) part 3?

Answer 5

that was for part 1

Answer 6

I know. But like 28 seconds?

Answer 7

what about the next part.

Answer 8

part 1 28 ft

Answer 9

ok :)

Answer 10

frankly speaking don't know the answer to part 2 but just give me some time i will try my best

Answer 11

yup don't worry! I appreciate your help

Answer 12

ok can u tell me the period for part 2 by looking at the information i have provided u (Given equation follows the form: y=Acos(Bx-C)+D, A=amplitude, period=2π/B, C/B=phase shift, D=vertical shif)

Answer 13

ummm no i dont know it :(

Answer 14

i suppose the given equation is H(t) = 20 cospi over 15 + 30

Answer 15

okay! true

Answer 16

H(t)=y

Answer 17

How would i solve that

Answer 18

u dont have to solve that

Answer 19

u have to substitute y in the place of H(t) in H(t) = 20 cospi over 15 + 30

Answer 20

But how will I get the answer to the last part...

Answer 21

Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?

Answer 22

y=Acos(Bx-C)+D

Answer 23

I have to answer that!

Answer 24

Can you help me?

Answer 25

u have to find the period for that

Answer 26

period=2π/B

Answer 27

the equation is y= 20 cospi over 15 + 30

Answer 28

yesss but how would i solve it :( i need to find the minimum

Answer 29

Given equation follows the form: y=Acos(Bx-C)+D

Answer 30

i am really sorry but i can't the information i provided with in this question was by taking the help of internet as i am not familiar with this chapter itself i tried my best sry

Answer 31

whatever its fine

Answer 32

but yes i can provide u with the answer of somewhat a similar quaetion

Answer 33

Travis is riding the Ferris wheel at the amusement park. His height can be modeled by the equation
H(t) = 22 cos (pi over 13)t + 28, where H represents the height of the person above the ground in feet at t seconds.
***
Given equation follows the form: y=Acos(Bx-C)+D, A=amplitude, period=2π/B, C/B=phase shift, D=vertical shift
..
For given equation: H(t) = 22 cos (pi over 13)t + 28
amplitude=22
B=π/13
period=2π/B=2π/(π/13)=26 sec
Phase shift=0
vertical shift=28
...
Part 1: How far above the ground is Travis before the ride begins?
H(0) = 22 cos (pi over 13)*0 + 28=22+58=50 ft
H(0) = 22 cos (0) + 28=22+58=50 ft
..
Part 2: How long does the Ferris wheel take to make one complete revolution?
period=2π/B=2π/(π/13)=26 sec
..
Part 3: Assuming Travis begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Travis' height above the ground reaches a minimum?
Cos function reaches a minimum at 1/2 period=13 sec
H(13)=22cos(π/13*13)+vertical shift of 28 up
H(13)=22cos(π)+vertical shift of 28
H(13)=22*(-1)+ 28=-22+28=6 ft

Answer 34

the only difference is that some of its values are different

Answer 35

was that helpful?