Question

Solve 4 log12 2 + log12 x = log12 96.

x = 88

x = 80

x = 12

x = 6

Answer 1

@IMStuck

Answer 2

Whenever you see log,
\[\log(x) = \log_{10}(x)\]

Now for the laws you need to solve this problem:

\[\log(a) + \log(b) = \log(ab)\]

\[\log(a^b) = b*\log(a)\]

Answer 3

Oh sorry forgot one,

\[a^{\log_a(x)} = x\]

For example,

\[12^{\log_{12}(x)} = x\]

\[5^{\log_{5}(x)} = x\]

Answer 4

Ok, when you end up with \[\log _{12}\frac{ 16x }{ 96 }=0\]that translates to \[12^{0}=\frac{ 16x }{ 96 }\]

Answer 5

That is because of this rule:

Answer 6

\[\log _{a}x=y-->x=a ^{y}\]

Answer 7

That's the hardest part of this one.

Answer 8

Anything to the 0 power = 1, so we have \[1=\frac{ 16x }{ 96 }\]

Answer 9

Now multiply both sides by 96 to get
96=16x

Answer 10

Now divide by 16 to get x = 6, your last choice up there.

Answer 11

This one was a stinky one. : P

Answer 12

@IMStuck your a lifesaver

Answer 13

TY for the medal, as well!