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what are the coordinates of the vertex of the function below? Write in the form (x,y)? y-9=-6(x-1)^2
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So to get this into a form where you can find the vertex, you need to get y by itself. This is simple enough, you add 9 to both sides. Your question now becomes: y=-6(x-1)^2+9 y=a(x-h)^2+k Where (h, k) is your vertex So your vertex is going to be (1, 9) Make sense?
So whenever I get these problems i just use the coordinates from the formula in the function?
Yes, your vertex will always be (h, k). Notice that the vertex is (1, 9) here even though you're subtracting the 1 -- if it was (x+1)^2, the vertex would be (-1, 9).
cool thank you
You're very welcome
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