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Mathematics 19 Online
OpenStudy (anonymous):

...

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

use law of sines

OpenStudy (anonymous):

a/sinA=b/sinB=c/sinC plug in the values given for b, A and B from the picture and solve for a

OpenStudy (anonymous):

You know how to find angle A right?

OpenStudy (anonymous):

|dw:1405048623528:dw|

OpenStudy (anonymous):

like that? im sure I am setting that up right

OpenStudy (anonymous):

Yes that is correct

OpenStudy (anonymous):

I dont know where to go next... like i do but i mess up more and then get confused more...

OpenStudy (anonymous):

Wait no you flipped the fractions it is the side lengths on top and the sin of the angle on bottom

OpenStudy (anonymous):

how will that look like?

OpenStudy (anonymous):

a/sin(45)=17/sin120

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

The next step is to find the values of sin(45) and sin(120)

OpenStudy (mathstudent55):

It makes no difference which is on top, the side length or the sine of the angle as long as all fractions are the same.

OpenStudy (anonymous):

Oh I was taught that way, but I think the way I said makes it easier to solve

OpenStudy (anonymous):

sin(45)=.7071 sin(120)=.8660

OpenStudy (anonymous):

yes so what is 17/.8660?

OpenStudy (mathstudent55):

The problem is asking for a. The circled proportion below has only "a" as an unknown and three known amounts. Use that proportion to solve for a. |dw:1405049068964:dw|

OpenStudy (mathstudent55):

Use cross multiplication to solve for a. Leave all sines as they are until the last step. Then enter all amounts in your calculator without rounding off. Round off only at the end.

OpenStudy (anonymous):

a=19.630 ?

OpenStudy (anonymous):

@mathstudent55

OpenStudy (mathstudent55):

I don't get that. Your expression is correct, though. \(\dfrac{\sin 45}{a} = \dfrac{\sin 120}{17} \) \(a = \dfrac{17 \sin 45}{\sin 120} \) What do you get now?

OpenStudy (anonymous):

13.88

OpenStudy (mathstudent55):

Correct.

OpenStudy (anonymous):

thank you! and thank you for your patience! :D

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