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use law of sines
a/sinA=b/sinB=c/sinC plug in the values given for b, A and B from the picture and solve for a
You know how to find angle A right?
|dw:1405048623528:dw|
like that? im sure I am setting that up right
Yes that is correct
I dont know where to go next... like i do but i mess up more and then get confused more...
Wait no you flipped the fractions it is the side lengths on top and the sin of the angle on bottom
how will that look like?
a/sin(45)=17/sin120
oh ok
The next step is to find the values of sin(45) and sin(120)
It makes no difference which is on top, the side length or the sine of the angle as long as all fractions are the same.
Oh I was taught that way, but I think the way I said makes it easier to solve
sin(45)=.7071 sin(120)=.8660
yes so what is 17/.8660?
The problem is asking for a. The circled proportion below has only "a" as an unknown and three known amounts. Use that proportion to solve for a. |dw:1405049068964:dw|
Use cross multiplication to solve for a. Leave all sines as they are until the last step. Then enter all amounts in your calculator without rounding off. Round off only at the end.
a=19.630 ?
@mathstudent55
I don't get that. Your expression is correct, though. \(\dfrac{\sin 45}{a} = \dfrac{\sin 120}{17} \) \(a = \dfrac{17 \sin 45}{\sin 120} \) What do you get now?
13.88
Correct.
thank you! and thank you for your patience! :D
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