Great integrals question – very stuck!! Shown below....help would be greatly appreciated!

Question

anonymous · Answer

The graph of the function $$y=\frac{ k }{ \sin2x }$$ where $$0<x<\frac{ \pi }{ 2 }$$ is given.
Find the value of 'k' such that the shaded area shown is equal to ln3

anonymous · Answer

The main problem is that I am not sure what the 'shaded area' is referring to as I am not provided with any diagram! ...

anonymous · Answer

I'm guessing k is just a scalar and that the region is from 0 to pi/2

anonymous · Answer

yeah thats what i assumed at the start, but it didnt end well...

anonymous · Answer

Yeah. Weird.

anonymous · Answer

...i figured that since the function is undefined between those intervals then the area under the graph has to be an infinite area....?

anonymous · Answer

Yeah. It's undefined at the boundaries of the interval, so that must not be the shaded region the problem refers to...

anonymous · Answer

exactly! ... thanks for your help, i'll let my teacher know and see what she says...

anonymous · Answer

Cool, glad to help.

anonymous · Answer

$$y=\frac{k}{\sin2x}=k\csc2x$$
which looks something like so
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