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The region R bounded by the curve 4y=x² and the lines x=4, y=1. Find the volume of the solid formed when R is rotated completely about (b) the y-axis (c) the line y=1(d) the line x=4 the answers should be (b) 18pi (c) 76pi/15 (d)10pi/3
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Something is wrong in here. \[ x=2\sqrt{y}\\ \begin{align*} \pi\int_0^1(2\sqrt{y})^2dy&=4\pi\int_0^1y\,dy\\ &=2\pi(y^2)|^1_0\\ &=2\pi \end{align*} \] How do you get \(18\pi\)?
@Callisto Help!
it should be x^2=4y
then looking at the graph the limits of integration are 1 to 4
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To me, for b) you should break it into 2 parts: \(\int_0^2 f(x) dx)) + volume of the cylinder washer from 2 to 4
|dw:1405078892920:dw|
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