Please Help...
Write an equation of a line in point slope form that has a slope of -3 and passes through the point
(3, -4).

Question

Please Help... 
Write an equation of a line in point slope form that has a slope of -3 and passes through the point
(3, -4).

johnnydicamillo · Answer

$$y+4 =-3(x-3)$$

anonymous · Answer

I Don't Understand.

anonymous · Answer

Point slope form is this y – y1 = m(x – x1)
where m is the slope

johnnydicamillo · Answer

Now just simplify the equation. Distribute the the "-3" and then subtract the 4 to both sides.

anonymous · Answer

y=-3x+5

anonymous · Answer

I subtract 4 from 5 and -3?

anonymous · Answer

no i gave you the answer, wait what lol

anonymous · Answer

She is trying to figure out how to do it

anonymous · Answer

Where did you get the 5 from?

anonymous · Answer

y-(-1)= -3 (x-3)
y+4= -3x+9
*subtract the 4 and minus it to the 9*
y=-3x+5

anonymous · Answer

i meant -4 not -1

anonymous · Answer

I'm extremely confused.. I've never done Algebra and my Geometry teacher never helped me so I have no idea how to do this.

anonymous · Answer

i showed you the work...

johnnydicamillo · Answer

Okay it is like this after you have the expression I gave you: $$y-y1 = slope(x - x1) where y1 and x1$$ where x1 and y1 is your point. So when you plug it in you get the equation $$y+4 = -3(x-3)$$ now you then distribute the "-3" so the equation looks like this: $$y+4 = -3x + 9$$ now subtract the 4 so it looks like this $$y = -3x + 5$$

johnnydicamillo · Answer

sorry funky answer. disregard the very first line

anonymous · Answer

you just basically plug in your points, (x,y) and your slope which is m; to the equation y-y1=m(x-x1)

johnnydicamillo · Answer

yes

anonymous · Answer

Ahh I understand now, Thank You Guys!!

anonymous · Answer

welcome (: