Question

simplify sec^2A (1-sin^2A)

Answer 1

what did you do so far?

Answer 2

im thinking of using the Pythagorean identity 1+tan^2u=sec^2u

Answer 3

typically, you want to simplify things...

going that way gives you more terms. see if there is something to take more terms into less terms

Answer 4

im stuck :(

Answer 5

look at the other thing... can you make that into something else?

Answer 6

sec^2x=1+tan^2x

Answer 7

no, look at the other term... (1-sin^2A)

Answer 8

I don't get it

Answer 9

here's another cheat sheet

Answer 10

\[1-\sin^2\left( A \right)=?\]\[\sec \left( A \right)=?\]

Answer 11

\[\sec \left( A \right)=\frac{ 1 }{ \cos \left( A \right) } \Rightarrow \sec \left( A \right)^2=\frac{ 1 }{ \cos \left( A \right)^2 }\]

Answer 12

oops, i meant\[\sec^2\left( A \right)=\frac{ 1 }{\cos^2\left( A \right) }\]

Answer 13

also,\[1-\sin^2\left( A \right)=\cos^2\left( A \right)\]

Answer 14

you need to know and understand these fundamental relationships...
The reiprocal functions of cosine, sine and tangent:\[\sec \left( x \right)=\frac{ 1 }{ \cos \left( x \right) }\]\[\csc \left( x \right)=\frac{ 1 }{ \sin \left( x \right) }\]\[\cot \left( x \right)=\frac{ \cos \left( x \right) }{\sin \left( x \right) }\]
the Pythagorean Identities:
\[\cos^2\left( x \right)+\sin^2\left( x \right)=1\]
\[\tan^2\left( x \right)+1=\sec^2\left( x \right)\]
\[\cot^2\left( x \right)+1=\csc^2\left( x \right)\]

Answer 15

I got one as the answer

Answer 16

that b correctamundo

Answer 17

yayy (: