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Chemistry 15 Online
OpenStudy (anonymous):

How many molecules (or formula units) are present in 1.00g of (NH4)2Cr7O2?

OpenStudy (anonymous):

N = 14g x 2 = 28g H = 1g x 8 = 8g Cr = 52g x 7 = 364g O = 16g x 2 = 32g Total MW. = 432g Total Moles = 1/432 moles x 6.022x10^23 Total molecules = 1.39x10^21 Check my calculations at the end here. I did not have a good calculator.

OpenStudy (anonymous):

I got something like that too but when I checked it in the back of my textbook it says 2.39x10^21 so I'm confused

OpenStudy (anonymous):

Typo in the book. It happens a lot.

OpenStudy (anonymous):

Alright then. Thank you!

OpenStudy (anonymous):

No problem. :-)

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