Question

verify sinA +cosA cotA=cscA

Answer 1

What is the definition of cot A?

Answer 2

cosx/sinx

Answer 3

So what is cos A (cos A/sin A)?

Answer 4

cosA is 1/secA

Answer 5

no im working on mine sorry

Answer 6

I am trying to help you learn something. Doing your homework for you will not help you.

Now so far you have:
\[ \sin A + \cos A \left( {{\cos A} \over {sin A}} \right) = \csc A\]

So what is

\[ \cos A \left( {{\cos A} \over {sin A}} \right) \] ?

What can you do to express this as one fraction?

Answer 7

its will be cos^2A/sinA

Answer 8

Then to add

\[ \sin A \]

to

\[ {{cos^2 A} \over {\sin A}} \]

\( \sin A \) has to have the same denominator. What can you do to \( \sin A \) to give it the same denominator?

Answer 9

So

\[ \sin A \left( {{\sin A} \over {\sin A}} \right) = \left( {{\sin^2 A} \over {\sin A}} \right) \]

Answer 10

Now

\[ {{\sin^2 A + \cos^2 A} \over {\sin A}} = \csc A\]

but what is
\[\sin^2 A + \cos^2 A \]
?

Answer 11

1

Answer 12

so what is the definition of \(\csc A \) ?

Answer 13

1/sinA

Answer 14

Then you are done.