Write down the following in order of size,smallest first. cos100 sin100 tan100
use a calculator
I hope that 100 here is in radians
cos(100) would be the largest as 100 radians lies in 4th quadrant and the only +ve function among all.
|sin(100)| < |tan(100)| but since both are negative. So, sin(100) > tan(100)
Thus, my preliminary answer would be: cos(100)>sin(100)>tan(100) And great I am correct
I am actually surprised :D
I believe 100 is in degree
cos 100 degree is less than 0
sin 100 is just under 1
tan 100 is almost - infinity
so tan 100<<cos100<sin100
But usually in a question if degree symbol is not used then it is assumed that the angle is in radians. After all, SI Unit is radians not degrees.
but for this case if it is in degree the sizes can be guessed. If it is in radians then we need to consult the calculator. I believe the question calls for understanding of the behaviour of the cos, sin and tan curves.
well even if it is in radians you can solve it without using calculator... except for division and multplication
ok thanks
@sheelo_mughal listen i am going to tell one thing which surprise u
listen sine function is increase from 0 to 90 and cos function decrease 0 to 90 and tan function also increase from 0 to 90 u can do it on yur calculator or from the trigonometric function like sin 30 = 0.5 sin 45 = 0.70 sin 60 = 0.866 sin 90 = 1 here it is showing that function is increasing so now u can u can found that first cos 100 will come first then sin and after it tan will come
@Haseeb96 , are you assuming the angles to be radian or in degrees ?
yes
radians ?
no degrees
Then sorry but cos(100) would not be maximum
As it will be negative and sin(100) would be positive
So, sin(100 degrees) > cos(100 degrees)
Correct order would be: tan(100 deg) < cos(100 deg) < sin(100 deg)
The overall answer is: \[\large{\boxed{\tan(100^\circ) < \cos(100^\circ) < \sin(100^\circ)}}\] and \[\large{\boxed{\cos(100)>\sin(100)>\tan(100)}}\]
Verified using calculator ^^^
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