Use a both elimination and substitution to solve this system of linear equations. Type your answer as an ordered triplet, like this: (-2, 4, 13) 2x−10y+1=z 4x + y = z + 18 -2x - 8z = y - 1
Ok, lets start by solving one of the equations for one of the variables. Which variable would you like to start with?
the first set
If I said a good place to start would be the variable z, why do you think that would be a good idea?
cause its easiest?
Right! It's already solved for. 2x−10y+1 = z z = 2x−10y+1 Ok so we know what z is equal too. Let's use this information to plug substitute what we got for z into one of the other equations.
The second equation has z by itself in there. Let's plug in 2x−10y+1 for z since z = 2x−10y+1 We would get from 4x + y = z + 18 To 4x + y = (2x - 10y +1) +18 Right? Do you have any questions so far?
not so far
Actually I'm making this harder than it needs to be. Let's actually solve for y in the second equation since it is by itself. 4x + y = z + 18 Comes to y = -4x + z + 18 Right? So we have, z = 2x−10y+1 y = -4x + z + 18
The order of steps can really make things complicated or easy depending on which route you take. The way I was doing it would have worked but would have been a nightmare to work through haha.
Are you with me so far? When you are, we can continue.
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