ALGEBRA 2 HELPPPP

Solve the following system of equations.

x + 3y + 2z = -16
2x - y + 2z = -15
2x - 2y - z = 1

(-3, -1, -5)
(-3, 5, -2)
(2, -4, -3)
(4, 4, -1)

Question

ALGEBRA 2 HELPPPP


Solve the following system of equations.

x + 3y + 2z = -16
2x - y + 2z = -15
2x - 2y - z = 1
 	
	(-3, -1, -5)
	(-3, 5, -2)
	(2, -4, -3)
	(4, 4, -1)

igreen · Answer

Okay, just plug in the solutions into each equation and see if they're true.

igreen · Answer

$x + 3y + 2z = -16$

$	(-3, -1, -5)$

$-3 + 3(-1) + 2(-5) = -16$

$-3 - 3 - 10 = -16$

$-6 - 10 = -16$

$-16 = -16$

This is true. Now let's move onto the next equation:

$2x - y + 2z = -15$

$(-3, -1, -5)$


$2(-3) + 1 + 2(-5) = -15$

$-6 + 1 + 2(-5) = -15$

$-6 + 1 - 10 = -15$

$-5 - 10 = -15$

$-15 = -15$

This is also true, now let's do the last equation:

$2x - 2y - z = 1$

$	(-3, -1, -5)$

$2(-3) - 2(-1) + 5 = 1$

$-6 - 2(-1) + 5 = 1$

$-6 + 2 + 5 = 1$

$-4 + 5 = 1$

$1 = 1$

This is also true.

So Option A is your answer.

anonymous · Answer

@iGreen thank you!