A system of equations is shown below: 3x + 8y = 12 2x + 2y = 3 Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. Show that the equivalent system has the same solution as the original system of equations.
Okay so in order to do this you want to multiply the second line by -4
ok so how?
Multiply every term in the second like by (-4)
oh kk
(-4)(2x+2y)= 3(-4)
-8x + -8y = -12
So now you can just cancel out the y if you subtract the equations. 3x + 8y = 12 -8x -8y = -12
So you would get -5x=0 then x=0, and to solve for y plug in x into any of the two.
Y=2/3
wait so y=0?
Wait no y=3/2
so x=0 then?
You just plug in x into any of the two equations
Yes that's what we solved first
ok so x=0 and y=3/2 and you substitute the values and solve
3(0) + 8y=12 then 8y=12 y=12/8 or 3/2
to check
Yeah
oh ok than i have to solve the original right?
We did solve the original. But umm I don't really get what the directions is asking for.
lol ok
3x+8y=12 -8x-8y=-12 would be an equivalent system and they would give you the same answer
Thanks a bunch!
Yeah, no problem babe.
3x + 8y = 12 2x + 2y = 3 -6x = 16y = -24 6x + 6y = 9 -10y = -15 /-10 /-10 y = 1.5 sub in y into the equation and solve for x :) @camerondoherty
yeah... Atleast I helped you
Anyways yeah you get the same answer y=3/1 or 1.5
I don't think shes online
Monster1234 take your plagiarism and leave this site. we don't want help from cheaters.
It's Russian
You could have linked that question instead of submitting it as your own
atleast you people actually hep others right? so why be so ungrateful
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