Will fan and medal
least common denominator
x^4 / x^2x+1 -8 / x^2+5x+4

Question

Will fan and medal
least common denominator
x^4 / x^2x+1    -8 / x^2+5x+4

anonymous · Answer

$$\frac{ x ^{4} }{ x ^{2}+2x+1  }  \frac{ -8 }{ x ^{2}+5x+4 }$$

anonymous · Answer

@DatTyGerTho

anonymous · Answer

I'm so confused

anonymous · Answer

yeah me too

larseighner · Answer

If you factor $x^2 + 2x +1$ it should give you a big clue what to try on the other one

anonymous · Answer

i tried can you walk me through it

larseighner · Answer

Factor $x^2 + 2x + 1$. then divide  $x^2+5x+4$ by one of the factors.

anonymous · Answer

can anyone walk me through this

anonymous · Answer

I'm just as confused as you are

anonymous · Answer

exactly this crap is hard

anonymous · Answer

@Abhisar

mathstudent55 · Answer

Start by factoring both denominators.

anonymous · Answer

i did after that i get confused

mathstudent55 · Answer

What did you get for the factorizations of the denominators?

anonymous · Answer

(x+1)(x-1)  (x+2)(x-2)

zehanz · Answer

The first denominator can be factored as $(x+1)^2$, so it has two factors x+1.
The second denominator can be factored as $(x+1)(x+4)$, so it has factors x+1 and x+4.

mathstudent55 · Answer

$\dfrac{ x ^{4} }{ x ^{2}+2x+1  } ~~~~~ \dfrac{ -8 }{ x ^{2}+5x+4 }$

$\dfrac{ x ^{4} }{ (x +1)(x + 1)  } ~~~~~ \dfrac{ -8 }{ (x +4)(x + 1) }$

Those are the correct factorizations.

anonymous · Answer

okay so the answer would be (x+1)^2 (x+4a)

mathstudent55 · Answer

Correct.

anonymous · Answer

without the a lol

anonymous · Answer

i have alot more if you dont mind helping with them

zehanz · Answer

Common denominators, have at least two factors x+1 and one factor x+4.

zehanz · Answer

I'll leave you in the able hands of @mathstudent55 :D

mathstudent55 · Answer

$\dfrac{ x ^{4} }{ (x +1)(x + 1)  } ~~~~~ \dfrac{ -8 }{ (x +4)(x + 1) }$

$\dfrac{ x ^{4} }{ (x +1)^2  } ~~~~~ \dfrac{ -8 }{ (x +4)(x + 1) }$

Once you get the prime facotrizations of the denominators, the LCD is the product of all common prime factors with larger exponent and and non-common prime factors

anonymous · Answer

ill tag one of you in the next one but the answer is (x+1)^2 (x+4)

mathstudent55 · Answer

Let's look a the prime factors:
Common factors: (x + 1)^2 and (x + 1): choose the larger exponent  ---> (x + 1)^2
Non=common factor: (x + 4) ---> choose it too

LCD: $(x + 1)^2(x + 4)$

anonymous · Answer

okay im gonna tag you in the next one or do you care if i just post it on here