Question

Pam is looking for a new car. She has test-driven two cars but can only purchase one. The probability that she will purchase car A is 0.46, and the probability that she will purchase car B is 0.34. What is the probability that she will not purchase either car A or car B?
0.12
0.40
0.20
0.80
________________________________________

Answer 1

The sum of all probabilities is 1.

Answer 2

Right.

Answer 3

0.46 + 0.34 = 0.80

So what is the probability she won't choose any of the cars? (Hint: Subtract from 1)

Answer 4

p(buy car A) + p(buy car B) + p(buy no car) = 1

Replace the two known probabilities by their numbers, and solve for p(buy no car).

Answer 5

Can you do that? @MACH1303

Answer 6

yes give me a sec

Answer 7

\(1 - 0.8 =~?\)

Answer 8

.2 my computer was messing with me thnx

Answer 9

No problem.

That's correct. :)

Answer 10

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