Question

Where are the asymptotes of f(x) = tan 2x from x = 0 to x = π?

Answer 1

x = 0, x = π, x = 2π

x = 0, x = pi over 4

x = pi over 4, x = 3 pi over 4

x = pi over 2, x = 3 pi over 2

Those are the options... i think its b or c

Answer 2

to calculate asymptotes of a given function u have to equate denominator with zero

Answer 3

yah thats what i did but i got pi/4

Answer 4

would it also be 0?

Answer 5

tan(x) is undefined when x = pi/2 and x = 3pi/2 for 0 < x < 2pi
Therefore, tan(2x) is undefined when x = pi/4 and x = 3pi/4 for 0 < x < pi

Answer 6

vertical asymptotes are the points at which the function is undefined

Answer 7

so pi/4 and 0 or pi/4 and 3pi/4

Answer 8

tan(x) = sin(x) / cos(x)
cos(x) = 0 when x = pi/2, 3pi/2 in the interval [0, 2pi]
Therefore, tan(x) has a vertical asymptote at x = pi/2, 3pi/2 in the interval [0, 2pi]
tan(2x) will have a vertical asymptote when 2x = pi/2, 3pi/2
or when x = pi/4, 3pi/4 in the interval [0, pi]

Answer 9

so d?

Answer 10

x = pi/4, 3pi/4

Answer 11

oh ok thanks

Answer 12

yw. (It is C)

Answer 13

could you help with more? ill best answer and post them