Trigonometry
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OpenStudy (anonymous):
What is the rate of change for f(x) = −2 cos 4x − 3 on the interval from x = pi over 4 to x = pi over 2?
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OpenStudy (anonymous):
@aum
negative pi over 16
negative 16 over pi
2 over pi
pi over two
hartnn (hartnn):
use this formula
\(\huge \dfrac{f(b)-f(a)}{b-a}\)
hartnn (hartnn):
basically you're finding the derivative, but over large interval, so we don't take limits.
you know how to find f(pi/2) and f(pi/4)
?
OpenStudy (anonymous):
no nor really
OpenStudy (anonymous):
im not that good with trig
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hartnn (hartnn):
to find f(pi/2), plug in x = pi/2 in f(x)
hartnn (hartnn):
to find f(pi/4), plug in x = pi/4 in f(x)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so a is pi/2?
OpenStudy (anonymous):
and b is pi/4?
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OpenStudy (anonymous):
or the other way around?
hartnn (hartnn):
doesn't matter :)
OpenStudy (anonymous):
ok so pi/8?
hartnn (hartnn):
pi/8 for what ?
OpenStudy (anonymous):
wait no pi/2! right?
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OpenStudy (anonymous):
for the rate of change?
OpenStudy (anonymous):
bc before its simplified, its 4pi/8!!! and then simplify
OpenStudy (anonymous):
i foud the common denominator and ssimplifed
hartnn (hartnn):
so you got pi/4 in the denominator, right ?
hartnn (hartnn):
ok,
f(pi/2) = -5
f(pi/4) = -1
numerator = -5-(-1) = -4
so,
rate = -4/(pi/4) = -16/pi
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OpenStudy (anonymous):
no i got 4pi/8
hartnn (hartnn):
thats incorrect
how u got that ?
OpenStudy (anonymous):
common denominator by getting 8 and multiplying each by 4 and 2
OpenStudy (anonymous):
or would you hve to go to 16?
hartnn (hartnn):
8
so,
|dw:1405108793616:dw|