Question

Guys could you help me solving this equation with a radical

Answer 1

x^2-2√2x=-2

Answer 2

\[x ^{2}-2\sqrt{2x} = -2 \]

This is the equation, right

Answer 3

yes

Answer 4

in my textbook says the answer is x=√2 but i cant get to that answer please help.!

Answer 5

Isolate the radical to one side of the equation.
Then square both sides to get rid of the radical.
Then solve for x.
Check each x and throw out extraneous solutions.

Answer 6

In the second term, is the x inside the radical sign or outside?

Answer 7

Hey you don't want to square it
if you know to to solve equation from 4th degree
just take your symbol is \[\sqrt{x} = y\]
\[y ^{4} - 2 \sqrt{2} y = -2\]

Answer 8

I think the x is outside the radical sign in which case ignore my previous steps.

Answer 9

well there is x^2 and 2x inside the radical sign

Answer 10

Can you solve 4th degree equation ??

Answer 11

hmm by what means

Answer 12

i can use common factor

Answer 13

Your answer of x = √2 works nicely when x is outside the radical sign.

Answer 14

oh

Answer 15

but i think is inside let me check

Answer 16

omg no it's not inside the radical omg im so blind

Answer 17

i meant that formula
https://proofwiki.org/wiki/Ferrari%27s_Method

Answer 18

x^2-2√2x=-2

Try x = √2
(√2)^2 - 2 * √2 * √2 = -2
2 - 4 = -2 which is true.

Answer 19

ok so i have to solve a 4th degree equation to get to the √2

Answer 20

after 1/2 hour! now that makes more sense and looks better than what i was working with

Answer 21

No if the answer is sqrt 2 then it isn't root x,so you have just 2nd degree function.

Answer 22

oh i get it nice.

Answer 23

If this is how it appears: 2√2x (x is outside the radical sign)
If this is how it appears: 2(√2x) or \(2\sqrt{2x}\) (x is inside the radical sign)

Answer 24

nope the x is outside

Answer 25

OK then medal aum and it's easy to be solved right?

Answer 26

I meant 2√(2x) above then x is inside the radical.

Answer 27

yeah thanks.